Need assistance

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masonsailor2
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Need assistance

Post by masonsailor2 »

I am not home for the next couple of days and I need some info. I need to know the distance the SS band saw blade travels in one revolution of the arbor.
Paul
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algale
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Re: Need assistance

Post by algale »

masonsailor2 wrote:I am not home for the next couple of days and I need some info. I need to know the distance the SS band saw blade travels in one revolution of the arbor.
Paul
IIRC, the band saw had 12" diameter wheels. The drive wheel is connected via its axle to the arbor via the power coupler, so one revolution of the arbor means one revolution of a 12" wheel. A band saw saw blade mounted on that wheel would be driven the equivalent of one full circumference of the wheel. Circumference is Pi x diameter which is Pi x 12" = 37.699"

We'll see if the engineers correct me. But that's my best guess.

By the way, what the heck do you need this information for?

Al
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masonsailor2
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Re: Need assistance

Post by masonsailor2 »

Thanks Al. I am going to have to build my own speed reducer using pillow blocks, shafts and v belt pulleys. I need to order the correct size pulley to get it down slow enough to cut the brass. I will just stick a pulley on the SPT output and then down to a shaft and then back up to a pulley on the bandsaw. Thanks again for the info !
Paul
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Re: Need assistance

Post by rpd »

masonsailor2 wrote:Thanks Al. I am going to have to build my own speed reducer using pillow blocks, shafts and v belt pulleys. I need to order the correct size pulley to get it down slow enough to cut the brass. I will just stick a pulley on the SPT output and then down to a shaft and then back up to a pulley on the bandsaw. Thanks again for the info !
Paul
Skip Campbell (MKC Tools) shows a couple he made on his web site. MK-V Jackshaft
Should give you the pulley sizes and mounting ideas. :)
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reible
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Re: Need assistance

Post by reible »

The shopsmith bandsaw is an 11" bandsaw but I have never attempted to actually measure the wheel size. So, if you will, every revolution will be 11/12*3.14 or about 2.88 feet

The shop smith reducer with a regular shopsmith is still pretty fast for cutting ferrous metals. That is if I remember right a 7:1 so the lowest on the stock shopsmith would then have a low speed 100 rpm.

SFM is then 288 (the 2.88 feet times the 100) again from memory 300 should be about top end for aluminum and brass.

So I guess you will need to shoot for that 7:1 and see what that brings, it may required a bit of extra work to get that with jack shaft and pulley arrangement.

If you lived closer I gladly loan you my speed reducer for this project. Any chance there is one on ebay or the like?

Ed
{Knight of the Shopsmith} [Hero's don't wear capes, they wear dog tags]
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algale
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Re: Need assistance

Post by algale »

reible wrote:The shopsmith bandsaw is an 11" bandsaw but I have never attempted to actually measure the wheel size. So, if you will, every revolution will be 11/12*3.14 or about 2.88 feet

The shop smith reducer with a regular shopsmith is still pretty fast for cutting ferrous metals. That is if I remember right a 7:1 so the lowest on the stock shopsmith would then have a low speed 100 rpm.

SFM is then 288 (the 2.88 feet times the 100) again from memory 300 should be about top end for aluminum and brass.

So I guess you will need to shoot for that 7:1 and see what that brings, it may required a bit of extra work to get that with jack shaft and pulley arrangement.

If you lived closer I gladly loan you my speed reducer for this project. Any chance there is one on ebay or the like?

Ed
I could be wrong, but I thought the 11" referred to the cut-off capacity of the blade in normal position, i.e. the horizontal distance between the blade and the "riser" of the case.
Gale's Law: The bigger the woodworking project, the less the mistakes show in any photo taken far enough away to show the entire project!

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Re: Need assistance

Post by rjent »

masonsailor2 wrote:Thanks Al. I am going to have to build my own speed reducer using pillow blocks, shafts and v belt pulleys. I need to order the correct size pulley to get it down slow enough to cut the brass. I will just stick a pulley on the SPT output and then down to a shaft and then back up to a pulley on the bandsaw. Thanks again for the info !
Paul

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Re: Need assistance

Post by JPG »

algale wrote:
reible wrote:The shopsmith bandsaw is an 11" bandsaw but I have never attempted to actually measure the wheel size. So, if you will, every revolution will be 11/12*3.14 or about 2.88 feet

The shop smith reducer with a regular shopsmith is still pretty fast for cutting ferrous metals. That is if I remember right a 7:1 so the lowest on the stock shopsmith would then have a low speed 100 rpm.

SFM is then 288 (the 2.88 feet times the 100) again from memory 300 should be about top end for aluminum and brass.

So I guess you will need to shoot for that 7:1 and see what that brings, it may required a bit of extra work to get that with jack shaft and pulley arrangement.

If you lived closer I gladly loan you my speed reducer for this project. Any chance there is one on ebay or the like?

Ed
I could be wrong, but I thought the 11" referred to the cut-off capacity of the blade in normal position, i.e. the horizontal distance between the blade and the "riser" of the case.
The wheels are a tad over 11". Blade to riser is just short of 11".

At 700 rpm that is about 2000 fpm.

FWIW almost 23 mph.
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reible
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Re: Need assistance

Post by reible »

When out and pulled the cover. Using this old scale it looks like it is quite near 11" including the tire.
IMG_0674sc.jpg
IMG_0674sc.jpg (114.39 KiB) Viewed 1235 times
Ed
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Ed in Tampa
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Re: Need assistance

Post by Ed in Tampa »

Yep! 11 inches!
Cir = dia x pi

About 2.88 feet

But I think the other Ed already said this :D
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